thomas algorithm example
\), \(x_3 = 0 - (-0.4167) \times 0.414 \approx 0 + 0.173 = 0.173\), \(x_2 = 0 - (-0.4) \times 0.173 \approx 0 + 0.069 = 0.069\), \(x_1 = 1 - (-0.4) \times 0.069 \approx 1 + 0.028 = 1.028\). Final solution: \[ x \approx \begin{bmat